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  4. Zn 2HCl = Zncl2 H2 Given that 0.05mol of zinc was added to 0.075mol of...

Zn 2HCl = Zncl2 H2 Given that 0.05mol of zinc was added to 0.075mol of...

Zn 2HCl = Zncl2 H2
Given that 0.05mol of zinc was added to 0.075mol of hydrochloric acid, calculate the amount (in mole) of excess reactant which remained unreached and the mass of ZnCL2 produced?
In A.D Rufa'i College for Legal and Islamic Studies
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Asked by Adeyeye on 4th March, 2023
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