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An object is thrown upward at a speed of 50 feet per second by a machine from a height of 11 feet off the ground. The height of the object after t seconds can be found using the equation s(t)=−16t^2+v0t+s0, where v0 is the initial velocity and s0 is the initial height. Give all numerical answers to 2 decimal places.
(a) When will the object reach its maximum height? seconds.
(b) What is its maximum height? feet.?
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Asked by deejay on 11th August, 2022
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