The appropriate concentration of HCL, in the stomach (stomach acid) is 0.17M , calculate the mass of the following antacids required to neutralize 50cm³ of this acid. a) Aluminum hydroxide Al (OH)3?

Emmyrosh

4 years ago

How many millimoles HCl do you have in 50 cc of the material?
That's mL x M = 0.17 x 50 = 8.5
NaHCO3 + HCl ==> NaCl + H2O + CO2
So you will need 8.5 millimoles NaHCO3 or 0.0085 mols.
grams NaHCO3 = mols x molar mass = ?

You do Al(OH)3 the same way but the equation is different.
Al(OH)3 + 3HCl ==> AlCl3 + 3H2O
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