Our website migration is now complete. If you experience any errors in pages, or if certain features are not functioning appropriately for you, we can fix it. Kindly contact us by DM, Email or Call.
The appropriate concentration of HCL, in the stomach (stomach acid) is 0.17M , calculate the mass of the following antacids required to neutralize 50cm³ of this acid. a) Aluminum hydroxide Al (OH)3?
Meekah20
8 Jun, 2022
To get notifications when anyone posts a new answer to this question
Answers (1)
Post your comment
Emmyrosh
4 years ago
How many millimoles HCl do you have in 50 cc of the material?
That's mL x M = 0.17 x 50 = 8.5
NaHCO3 + HCl ==> NaCl + H2O + CO2
So you will need 8.5 millimoles NaHCO3 or 0.0085 mols.
grams NaHCO3 = mols x molar mass = ?
You do Al(OH)3 the same way but the equation is different.
Al(OH)3 + 3HCl ==> AlCl3 + 3H2O
I
Share:
Quick Questions
Chioma667
2 Nov, 2021
When will federal college of education eha-amufu ends the registration of post utme form?
2 comments
ozoana86collins
12 Jan, 2020
Is there any clinic or hospital located in Federal college of education Eha amufu, Enugu and other federal colleges of Education?
1 comments