algebraic faction , reduce to the lowest term ,6m² u² -4mu³/9m³ u-4mu³?


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Robert01
4 years ago

(6m²u² - 4mu³)/(9m³u - 4mu³)

First, factorise the numerator and denominator.

(2mu²)(3m - 2u)/(um)(3²m² - 2²u²)

Then, difference of two squares can be applied to the denominator

(2u)(3m - 2u)/(3m - 2u)(3m + 2u)

Thus,

(2u)/(3m + 2u)

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