A body at rest is given an initial uniform acceleration of 8m/s^2 for the next 20seconds. The body maintains the speed attained for 60seconds. after which it is brought to rest in 20seconds. (a) draw the velocity time graph of the motion, using the information given above (b) using the sketch calculate the (1) maximum speed attained during the motion (2) average retardation as the body is being brought to rest (3) total distance traveled during the first seconds?
Dodionstephen
17 Nov, 2021
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Emmyrosh
4 years ago
Solution
1. If you have drawn the graph correctly it must give you the answer to 1 straigt away from graph.
It is 30*8 + 5*20 = 340 m/s
2. Required average retardation = 340/20 - 17 m/s^2
3. From correct graph you can calculate this as area under graph from t= 0 to 50 s
Otherwise required s = 0.5*8.0*30^2 + 240*20 + 0.5*5.0*20^2 = 3600 + 4800 + 1000 = 9400 m
4. Required average velocity = 9400/50 = 188 m/s
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