calculate the number of moles of atoms present in 10 gram of Na2 CO3 sodium trioxocarbonate IV acid?

Modudharniel16

6 years ago

number of moles = mass / molar mass
molar mass of Na2CO3 = 23 * 2 + 12 + 16 * 3
molar mass = 106g/mol
moles = 10/106
mole of Na2CO3= 0.094 moles

Ayomicourage

6 years ago

No of moles = reacting mass/molar mass
molar mass of Na2C+3=105
no. Of moles = 10/105
No of moles = 0.095mole

Aliyuus2

6 years ago

solution
no of moles = reacting mass/molar mass
molar mass of Na2co3=23×2+12+16×3=
46+12+48
106
= 10/106=0.094 moles