if the volume of a given mass of gas at 0°c is 36cm cube determine the temperature at which it's volume becomes 48 cm cube assuming that the pressure remains unchanged.?
Benedictudo
22 Apr, 2020
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hannansayeed2030
6 years ago
T1=0°c=273k
T2=?
v1=36cm³
v2=48cm³
v1/t1 = v2/t2
36/273 = 48/t2
t2 × 36 = 48×273
divide both sides by 36
36×t2/36 = 13104/36
t2= 13104/36
:. t2= 364k or 91°c
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