the interior angles of a pentagon are; (q 13)°,(q 5)°,(q 23)°,(q 29)° and (q 40)°...

the interior angles of a pentagon are; (q 13)°,(q 5)°,(q 23)°,(q 29)° and (q 40)° find the value of q. find the value of each of the interior angle. please note that addition sign is between q and value. the signs keep disappearing after posting. thanks.?

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Answers (4)

Vek Tor
1 month ago
The sum of the interior angles is (2n-4) right angles
where n=5
(y+13) + (y+5) + (y+23)(y+29) + (y+40)=(2*5-4)
5y+110degree=6 right angles

where right angle=90degree

5y+110degree=6*90
5y+110degree=540degree
5y=540degree-110degree
5y=430degree
make y the subject of the formula
y=430/5
y=86degree...ans
evan
1 month ago
Pentagon has 5 sides
interior angle =(2n-4)90=(2x5-4)90 =6x90=540

13+q+5+q+q+23+q+29+q+40=540

5q+110=540
5q=540-110=430
q=430/5=86

therefore th angles are

13+86=99
86+5=91
86+23=109
86+29=115
86+40=126
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