Gain 200 level admission into any university - no JAMB and low fees

A copper calorimeter weighing 40g contains 200g of water at 30 degree celuis.20g of dry...

A copper calorimeter weighing 40g contains 200g of water at 30 degree celuis.20g of dry ice is added to the water and this reduces the temperature to 25 degree celcuis after all the ice has melted.what volume of the specific latent heat of fussion of ice is given by this experiment.take c(water)=4200jkg/k and c(calorimeter)=400jkg/k?

To get notifications when anyone posts a new answer to this question,
Follow New Answers

Post an Answer

Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here

JAMB 2020 CBT Mobile App - Download Now, It's Free!
JAMB 2020 CBT Software - Download Now, It's Free!

Answers (1)

james
1 month ago
M1(mass of calorimeter)=40g
M2(mass of watet+calorimeter)=200+40=240g
M3(mass of water+calorimeter+ice)=200+40+20=260g
@1=30'
@2=25'
C1(calorimeter)=400jkg/k
C2(water)=4200jkg/k
L=?


Q=ML
L=Q/M

where M(ice)=M3-M2
Q=MC(@1-@2)
M(water)=M2-M1


L=[(M2-M1)(Cw)(@1-@2)]/(M3-M2)
L=[(240-40)(4200)(30-25)]/(260-240)
L=(200*4200*5)/20
L=10*4200*5
L=210,000J/Kg
OR
L=210KJ/Kg
Ask Your Own Question See More Borno State University Questions
 
JAMB 2020 CBT Software - Download Now, It's Free!
JAMB 2020 CBT Mobile App - Download Now, It's Free!
JAMB 2020 CBT Software Agents - Click Here to Apply