A copper calorimeter weighing 40g contains 200g of water at 30 degree celuis.20g of dry...

A copper calorimeter weighing 40g contains 200g of water at 30 degree celuis.20g of dry ice is added to the water and this reduces the temperature to 25 degree celcuis after all the ice has melted.what volume of the specific latent heat of fussion of ice is given by this experiment.take c(water)=4200jkg/k and c(calorimeter)=400jkg/k?

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Answers (1)

AaCcTt
7 months ago
M1(mass of calorimeter)=40g
M2(mass of watet+calorimeter)=200+40=240g
M3(mass of water+calorimeter+ice)=200+40+20=260g
@1=30'
@2=25'
C1(calorimeter)=400jkg/k
C2(water)=4200jkg/k
L=?


Q=ML
L=Q/M

where M(ice)=M3-M2
Q=MC(@1-@2)
M(water)=M2-M1


L=[(M2-M1)(Cw)(@1-@2)]/(M3-M2)
L=[(240-40)(4200)(30-25)]/(260-240)
L=(200*4200*5)/20
L=10*4200*5
L=210,000J/Kg
OR
L=210KJ/Kg
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