please help solve this: three angles of a nonagon are equal and the sum of the six other angels is 1050 degrees.obtain the size of one of the equal angles.?

Speechlez

8 years ago

Total sum of "interior" angles in any polygon = (2n - 4) X 90 degrees.
Since nonagon has 9 sides, therefore n=9
(2X9 - 4) = 18 - 4 = 14
14 X 90 degrees = 1260 degrees.
Subtract the sum of other six angles (i.e 1110 degrees) from total sum of all interior angles (i.e 1260 degrees), that will give you 150 degrees.
Now, since there are 3 equal angles, to get one of the angle, you have to divide 150 degrees by 3. And that will give you 50 degrees