90% of Post UTME Exam Questions come from Past Ones
Failed JAMB? Don't Worry, you can gain admission into 200L in any University of your Choice, even with low JAMB Score

If x,y,z share a sum of N68 and for every N1 that z gets, y...

If x,y,z share a sum of N68 and for every N1 that z gets, y gets N2 and for every N3 that y gets, x gets N4. How much does y get?

To get notifications when anyone posts a new answer to this question,
Follow New Answers

Post an Answer

Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here

Post UTME Past Questions 2019/2020
Get Project Topics & Materials

Answers (8)

YK.
5 years ago
This shows dat y is twice d value that z gets which is 2:1.And for every N3 that y gets x gets N4 which is 4:3 multiplying by 2,its 8:6 then z is half of y the ratio is 8:6:3 for x,y,z resp. d total =17,.'. y gets (6/17) x 68=6x4= N24.
mayok2
5 years ago
#24
joseomoniger
5 years ago
y gets 24 ...
berber
5 years ago
Y gets N24
gizzyboy
5 years ago
Itz N24
dappz
5 years ago
1z=2y

3y=4x = 3y/4=x

3y/4+y+2y=68 3y+4y+8y= 272

15y/15=272/15

y=18.1
Jazzgreen
5 years ago
24
Ask Your Own Question

Quick Questions

See More Mathematics Questions
 
Post UTME Past Questions 2019/2020
Sell Past Questions on Myschool
Get Project Topics & Materials