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If x,y,z share a sum of N68 and for every N1 that z gets, y...

If x,y,z share a sum of N68 and for every N1 that z gets, y gets N2 and for every N3 that y gets, x gets N4. How much does y get?

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Answers (8)

YK.
5 years ago
This shows dat y is twice d value that z gets which is 2:1.And for every N3 that y gets x gets N4 which is 4:3 multiplying by 2,its 8:6 then z is half of y the ratio is 8:6:3 for x,y,z resp. d total =17,.'. y gets (6/17) x 68=6x4= N24.
mayok2
5 years ago
#24
joseomoniger
5 years ago
y gets 24 ...
berber
5 years ago
Y gets N24
gizzyboy
5 years ago
Itz N24
dappz
5 years ago
1z=2y

3y=4x = 3y/4=x

3y/4+y+2y=68 3y+4y+8y= 272

15y/15=272/15

y=18.1
Jazzgreen
5 years ago
24
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