An electric motor running at 300rev/min does 920J of work per second. (1)what is the...

An electric motor running at 300rev/min does 920J of work per second. (1)what is the torque of the motor spindle? (2)what force is being exerted,if the radius of the spindle is0.3m?

To get notifications when anyone posts a new answer to this question,
Follow New Answers

Post an Answer

Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here

JAMB 2020 CBT Software - Download Now, It's Free!
JAMB 2020 CBT Software Agents - Click Here to Apply

Answers (1)

Cletus300
6 years ago
Torque= force/radius

= 184/0.3 = 613.3N/M

Force exerted= mv^2/r = 18.4*5^2/0.3= 1500N
Ask Your Own Question

Quick Questions

See More Physics Questions
 
JAMB 2020 CBT Mobile App - Download Now, It's Free!
JAMB 2020 CBT Software - Download Now, It's Free!
JAMB 2020 CBT Software Agents - Click Here to Apply