# Given data percent_C = 62.1 percent_H = 10.3 percent_O = 27.5 atomic_mass_C = 12...

# Given data
percent_C = 62.1
percent_H = 10.3
percent_O = 27.5

atomic_mass_C = 12
atomic_mass_H = 1
atomic_mass_O = 16

# Step 1: Calculate moles of each element in 100g
moles_C = percent_C / atomic_mass_C
moles_H = percent_H / atomic_mass_H
moles_O = percent_O / atomic_mass_O

# Step 2: Find the molar ratio (divide by smallest)
min_moles = min(moles_C, moles_H, moles_O)

ratio_C = moles_C / min_moles
ratio_H = moles_H / min_moles
ratio_O = moles_O / min_moles

print(f"{moles_C=}, {moles_H=}, {moles_O=}")
print(f"{ratio_C=}, {ratio_H=}, {ratio_O=}")

# Empirical formula mass
# C3 H6 O1
empirical_mass = 3*12 + 6*1 + 16

# Molecular mass
molecular_mass = 58.0
n = molecular_mass / empirical_mass
print(f"{empirical_mass=}, {n=}")?

In Chemistry
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Asked by Chizitere on 4th April, 2026