1g CaCo3 was treated with excess 0.1M HCl at the end of the reaction, the...
1g CaCo3 was treated with excess 0.1M HCl at the end of the reaction, the...
1g CaCo3 was treated with excess 0.1M HCl at the end of the reaction, the acid left untreated required 25cm3 of 0.1M Na2CO3 to neutralize it. What was the original volume of the acid (Na=23, Ca =40, C =12, O =16,Cl =35.5)?
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Asked by Adefemi on 9th April, 2024
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