In the electrolysis of CuSo4(g) using platinum electrode the reaction at the anode is
A. 4H+ 4e - 2H2
B. 4OH= 4e- + 2H2O + O2
C. 2OH - 2e- = 2OH
D. 2OH- + 2OH = 2H2O + O2
The answer is B but why??
In Chemistry
2 Answers Available
Asked by Lanre on 29th March, 2024
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