3resistors with resistance 250hrm,500hrm and 1khrm are connected in series,A 6volt battery is connected to either end of the combination.calculate the potential difference between the ends of the 250hrm resistor.?

All_for_one

2 years ago

To calculate the potential difference across the 250-ohm resistor in the given circuit, we can use the formula V = I * R, where V is the potential difference, I is the current, and R is the resistance.

First, we need to find the total resistance of the circuit, which is the sum of the individual resistances:
Total resistance (R_total) = 250 ohm + 500 ohm + 1000 ohm = 1750 ohm

Next, we can use Ohm's law to find the current flowing through the circuit:
I = V / R_total
I = 6V / 1750 ohm
I ≈ 0.00343 A

Now that we know the current, we can find the potential difference across the 250-ohm resistor:
V_250ohm = I * 250 ohm
V_250ohm ≈ 0.00343 A * 250 ohm
V_250ohm ≈ 0.8575 V

Therefore, the potential difference across the 250-ohm resistor is approximately 0.8575 volts.