A mass m of water at 100celsuis is added to another mass m of water at temp T and the resulting is T.if the S.H.C of water is 4200j. Derive an expression of T in terms of other quantities?

vault

2 years ago

mc( T2 - 100 ) = mc ( T3 - T2 )
making T2 the the subject of the formula and cancelling others we have
2( T2 ) = T3 + 100
T2 = (T3 + 100)/2
T2 = T3/2 + 50
note T2 is the final temperature of the mixture the specific heat capacity constant is not needed because it will still cancel out the tge the mass thank you