what is the p.e of a mass of 1kg situated at the surface of the earth? where Re=6.4×10^6m(Re= radius of the earth)?

Qawsw

2 years ago

The potential energy (PE) of an object due to gravity is given by:

PE = m × g × h

where:
m = mass (1 kg)
g = acceleration due to gravity (approximately 9.8 m/s^2)
h = height (distance from the center of the Earth)

Since the object is at the surface of the Earth, the height (h) is equal to the radius of the Earth (Re):

h = Re = 6.4 × 10^6 m

Now, plug in the values:

PE = 1 kg × 9.8 m/s^2 × (6.4 × 10^6 m)
= 62,912,000 J
= 62.9 MJ

So, the potential energy of the 1 kg mass at the surface of the Earth is approximately 62.9 megajoules.