A stone is projected vertically upward with a velocity of 20m/s. Two seconds later a second stone is similarly projected with the same velocity. When the two stones meet, the second one is rising at a velocity of l0m/s. Neglecting air resistance, calculate the (i) length of time the second stone is in motion before they meet. (ii) Velocity of the first stone when they meet. (Take g = l0m/s2).?
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Asked by Claude on 7th September, 2023
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