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A uniform metre rule of mass 100g balanced horizontally on pivot at it's 45cm mark....

A uniform metre rule of mass 100g balanced horizontally on pivot at it's 45cm mark. When load of 20g is hung on 10cm mark and 30g on y distance away from the left side of the pivot and 50g which is x distance away from the right side of the pivot
Use this information to show that y=5/3(1 x)?

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WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC offline past questions - with all answers and explanations in one app - Download for free
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709