A uniform metre rule of mass 100g balanced horizontally on pivot at it's 45cm mark. When load of 20g is hung on 10cm mark and 30g on y distance away from the left side of the pivot and 50g which is x distance away from the right side of the pivot
Use this information to show that y=5/3(1 x)?
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Asked by gift on 26th July, 2023
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