A contains 12.0 g of impure NaHSO, per dm' of solution;
B contains 2.0 g of pure NaOH per 500 em' of solution.
In a titration experiment 20.0 em of B required an average of 18.33 cm of A for complete neutralization. Calculate the
a. amount of NaOH in 1 dm of B:
b. concentration of NaHSO, in mol dm of A:
c. mass of NaHSO, in 12.0 g of the sample;
d. percentage of NaHSO, in the sample.
[H = 1.0: 0 = 16; Na = 23: S = 32]
The equation for the reaction is:
NaHSO, (g) + NaOHay) -* Na,SO 4am) +11-Ow?
3 Answers Available
Asked by Sixtus on 22nd January, 2023
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