The result show that 25.00cm of 0.1M potassium hydroxide is needed to neutralise 24.10cm tetraoxosulphate...
The result show that 25.00cm of 0.1M potassium hydroxide is needed to neutralise 24.10cm tetraoxosulphate...
The result show that 25.00cm of 0.1M potassium hydroxide is needed to neutralise 24.10cm tetraoxosulphate (vi) acid, whose concentration has to be determined. (H2SO4 =98,KOH=56)?
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Asked by Funke on 8th December, 2022
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