Three years ago, a man was four times as old as his son is now....

Three years ago, a man was four times as old as his son is now. The product of their ages is four hundred and thirty (430).
Compute the ages of both the man and his son as of now. (workings are to be shown)?

In Mathematics
2 Answers Available
Asked by Jennifer on 16th November, 2022

WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995

WAEC offline past questions - with all answers and explanations in one app - Download for free

WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709

To get notifications when anyone posts a new answer to this question,
Follow New Answers

Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts

Answers ({{ comment_count }})

Please wait...

{{ settings.no_comment_msg ? settings.no_comment_msg : 'There are no comments' }}

Ask Your Own Question

Quick Questions

What is the difference between 2:45am and 12:32pm A. 9Hrs 47min B. 14Hrs 10min C. 5Hrs 25min D. 10Hrs 17min? Answer this

4 Answers · Mathematics · 1 year ago
A point X is 34m due east of a point Y .the bearing of a flagpole from X and Y... Answer this

2 Answers · Mathematics · 3 years ago
A triangle has sides 8cm and 5 cm and an angle of 90 ° between the . calculate the smallest... Answer this

1 Answers · Mathematics · 21 hours ago

See More Mathematics Questions

Three years ago, a man was four times as old as his son is now....

Post an Answer

Answers ({{ comment_count }})

Please wait...

Modal title

Report

Block User

{{ feedback_modal_data.title }}

Quick Questions

Sign In