1.0g of CaCO3 was treated with excess 0.1M HCl. At the end of the reaction, the acid still left unreacted required 25cm³ of 0.1M Na2CO3 to neutralise it. What is the volume of the original acid? [Na=23, Ca=40, O=16, S=32, Cl=35.5?
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Asked by Emmysnr on 14th November, 2021
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