Calculate the volume of 0.25M solution of tetraoxosulphate (vi) that will contain a mass of 4.5g of the raw acid. [H=1,S=32,O=16].?

Emmyrosh

4 years ago

Using n = C x V
m/M = C x V
4.5/98 = 0.25 x V
Making V the subject of the formula,
V = 4.5/(98 x 0.25)
V = 0.184dm^3 or 184cm^3 (ANSWER)
Note: Molar mass of H2SO4 = 98g/mol
number of mole(n) = mass(m)/molar mass(M)