*A STONE IS PROJECTED VERTICALLY UPWARD WITH A VELOCITY OF 20M/S.TWO SECONDS LATER A SECOND STONE IS SIMILARLY PROJECTED WITH THE SAME VELOCITY. WHEN THE TWO STONE MEET, THE SECOND ONE IS RISING AT A VELOCITY OF 10M/S. NEGLECTING AIR RESISTANCE, CALCULATE THE*
*1) LENGTH OF TIME THE SECOND ONE IS IN MOTION BEFORE THEY MEET*
*2) VELOCITY OF THE FIRST STONE WHEN THEY MEET (g=10M/S^2)*?
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Asked by Jerrycurl👨🏽🔬 on 3rd July, 2021
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