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Al2(SO4)3. 2H2O 2 * 27 + 3*32 + 14 * 16 + 4 * 1...

Al2(SO4)3. 2H2O


2 * 27 + 3*32 + 14 * 16 + 4 * 1 =
54 + 96 + 224 + 4 = 378
% O2 = (224/378) * (100/1) = 59.25%
How did 14 come about in this answer? Considering that we are finding the mass percentage of oxygen the compound
In Chemistry
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Asked by Franklin on 18th May, 2021
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