a boy at a point A walks 20 km upwards to another point B. from point B he walks 15km Eastward to a 3rd point C . from point C,he walks 80km southwards to a point D and 10km westward to a point E . what is the shortest distance between A&E?

Robert01

5 years ago

The shortest distance between A and E = Displacement.

X-component:
20cos90° + 15cos0° + 80cos270° + 10cos180°= 0 + 15 – 0 – 10= 5km

Y-component:
20sin90° + 15sin0° + 80sin270° + 10sin180°= 20 + 0 – 80 + 0= –60km

Displacement= √(5² + (–60)²)= √(25 + 3600)= √3625= 60.21km

OR

Using Pythagoras theorem,

AE= √(5² + 60²)= √3625= 60.21km