the quantity why is partly constant and partly varies inversely as the square of x A)write down the relationship between x and y B when x is equal to 1 y is equal to 1 and when x is equal to 2 y is equal to 5 find the value of y when x is equal to 4?
precious_2
1 Apr, 2021
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VTPETERS2002
5 years ago
(a) y=k+c/(x^2)
(b) y=2.125
Step-by-step explanation:
(b) 11=k+c.....1
5=k+c/4.....2
using elimination method;
-3k=9
k=-3
substitute, k=-3, into equation 1
c-3=11
c=14
therefore; y=c/(x^2) -3
y=14/(16) -3
y=2.125
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