If 465cm3 of sulphur (iv) oxide, can diffuse through porous partition in 30 secs, how...
If 465cm3 of sulphur (iv) oxide, can diffuse through porous partition in 30 secs, how...
If 465cm3 of sulphur (iv) oxide, can diffuse through porous partition in 30 secs, how will (a) an equal volume, (b) 620cm3 of hydrogen sulphide take to diffuse through same partition? (H=1,S=32,O=16)?
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Asked by Okoweh on 14th January, 2021
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