Some copper (ll) sulphate pentahydrate (CuSO4 5H2O), was heated at 120 oC with the following results. Wt of crucible = 10.00 g; Wt of crucible + CuSO4 5H2O =14.98g; Wt of crucible + residue = 13.54 g. How many molecules of water of crystalization were lost?
[H = 1, Cu = 63.5, O = 16, S = 32]
A. 1
B. 2
C. 3
D. 4
E. 5
(Please, Show your work in detail)?
2 Answers Available
Asked by Alex on 19th August, 2020
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