Good morning all,Please guys, help me with this problem: A stone is projected vertically upward...

Good morning all,Please guys, help me with this problem: A stone is projected vertically upward with a velocity of 20ms-¹. Two seconds later, a second stone is similarly projected with thesame velocity. When the two stones meet, the second one is rising at a velocity of 10ms-¹. Neglecting air resistance, calculate the;
(I) The length of time the second stone is in motion before they meet.
(II) Velocity of the first stone when they meet. {Take g=10ms-²}
Thanks to as many that will attempt this.... 😇😇😇?

In Physics
4 Answers Available
Asked by Jay_Grace on 31st July, 2020