if the radius of a planet is 8×10^5 m the escape velocity of a satalite of the planet is?

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Afolayan

3 weeks ago

3 weeks ago

escape velocity (e)= √2gr

where:

g = 10m/s

r = 8×10^5 m

e = √(2x10x 8×10^5 )

= √(2x 8×10^6 )

= √(16×10^6 )

e = 4000ms^-1

where:

g = 10m/s

r = 8×10^5 m

e = √(2x10x 8×10^5 )

= √(2x 8×10^6 )

= √(16×10^6 )

e = 4000ms^-1

Ay.Khaleed

3 weeks ago

3 weeks ago

⇒3x / 4 - 7 / 4 = 5x +12

⇒3x / 4 -5x = 12 + 7 / 4

⇒(-17x) / 4 = 55 / 4

⇒x = (55 / 4) * (4 / (-17))

= -55 / 17

⇒3x / 4 -5x = 12 + 7 / 4

⇒(-17x) / 4 = 55 / 4

⇒x = (55 / 4) * (4 / (-17))

= -55 / 17

3 weeks ago

where:

g = gravity = 10m/s

r = radius of the planet = 8×10^5 m

escape velocity = squareroot(2x10x 8×10^5 )

escape velocity = squareroot(2x 8×10^6 )

escape velocity = squareroot(16×10^6 )

escape velocity = 4000m/s