1. A uniform bar XY of mass 5.0 kg and length 300 cm is suspended by two inextensible identical wires P and Q. P is attached 50 cm from the end X and Q to the centre of mass C of the bar, such that they are vertical. A mass of 10.0 kg is attached to the end X of the bar.
Determine the distance from the centre of mass C where another mass of 10.0 kg should be hung on the bar to keep the bar horizontal and to make the tension in Q four times the tension in P. [g = 10ms-2].?
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Asked by sanz on 30th May, 2020
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