### Ethane burns completely in oxygen according to the equation below; C2H6(g) + 7/2 O2(g) →...

Ethane burns completely in oxygen according to the equation below; C2H6(g) + 7/2 O2(g) → 2CO2(g) + 3H2O(g)
What is the amount in moles of carbon (IV) oxide will be produced when 6.0g of ethane are completely burnt in oxygen.?

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Explanation:
Balanced Eqn
2C2H6 + 7O2 = 4CO2 + 6H2O
By the Balanced eqn
60g ethane requires 7x32= 224g oxygen
here ethane is in excess.oxygen will be
fully consumed
hence
300g oxygen will consume
60 ⋅ = 80.36g ethane
leaving (270-80.36)= 189.64 g ethane.
By the Balanced eqn
60g ethane produces 4x44 g CO2
hence amount of CO2 produced =
4 ⋅ 44 ⋅ = 235.72g
and its no. of moles will be =5.36
where 44 is the molar mass of Carbon
dioxide
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• K: why the use of 60g instead of 6g
1 month ago
• JP: why did you use 60g instead of 6g
1 month ago
Molar mass of ethane = 2*12+6*1=30g/mol . amount of ethane = 6/30=0.2mol . since the mol ratio of ethane to carbon(iv)oxide is equal to 1:2, then amount of CO2= 2*0.2 = 0.4mol .
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