When a heavy cable hangs under gravity, the length of the cable is given by the formula 2c sinh L/2c,where L is the span and c is the horizontal tension divided by the weight per unit length. Determine the length of the cable that weighs 5/8kN per m strained with a horizontal tension of 40kN, the span being 48m.?
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Asked by Favour on 25th April, 2020
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