WAEC 2002
A horizontal door of a submarine at a depth of 500m has an area of 0.4^2.
Calculate the force exerted by the sea water on the door at this depth.
[Relative density of sea water =1.03] [Atmospheric pressure= 1.0 × 10^5N/m^2] [Density of water=1000kg/m^3] [g= 10m/s^2].?
In Physics
5 Answers Available
Asked by Matthew on 24th April, 2020
Ask Your Own Question
Quick Questions
See More Physics Questions
Answers ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}