What mass of ice at -14 degree celsius will be needed to cool 200cm3 of an orange drink(essentially water)from 25degree celsius to 10degree celsius(specific latent heat of fusion of ice =3.36*10^5 jkg^-1, specific heat capacity of ice =2100 jkg^-1 k^-1, specific heat capacity of water=4200 jkg^-1 k^-1)?
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Asked by evan on 20th April, 2020
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