in the reaction represented by the equation C H²O----CO H² carried out at 27degrees calcium,...

in the reaction represented by the equation
C H²O----CO H²
carried out at 27degrees calcium, the enthalpy change was 45000J and the entropy change was 12JK\1. calculate d free energy change?

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Answers (1)

God'swill
3 months ago
Enthalpy change = 45,000 J
Entropy change = 12J/K^-1
Temp. = 27 + 273 = 300k
Gibbs free energy change = (45,000) - (300*12) = 45,000 - 3,600 = 41,400J
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