Cr2O72-(aq) + 14H+(aq) + 6l-(aq) → 2Cr3+(aq) + 3l(g) + 7H2O(I).
The change in the...
Cr2O72-(aq) + 14H+(aq) + 6l-(aq) → 2Cr3+(aq) + 3l(g) + 7H2O(I).
The change in the...
Cr2O72-(aq) + 14H+(aq) + 6l-(aq) → 2Cr3+(aq) + 3l(g) + 7H2O(I).
The change in the oxidation number of oxygen in the equation above is?
A. 0
B. 1
C. 2
D. 7
Please explain😔?
InChemistry
1 Answers Available
Asked by Vek Tor on 12th February, 2020
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