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A 8kg mass rests on an inclined plane. If the limiting frictional force of 50N...

A 8kg mass rests on an inclined plane. If the limiting frictional force of 50N and g=10m/s2, then the angle of inclination of the plane is?

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Answers (6)

EmX
1 week ago
  • EmX: Lets solv it anther way, Just for fun.
    its longer and uneccessary to some extent, but no Knowlege is a waste ryt?馃榿
    Like 1    Dislike 0   1 week ago
Davy
1 week ago
mizta smart
1 week ago
isaaq
1 week ago
Solution
M*g = 8 * 10 = 80 N.

Fp = 80*sin A = Force parallel with the incline.

Fp - Fs = M*a,
80*sinA - 50 = 8 * 0,
80*sinA - 50 = 0,
A = 38.7 deg.

Fs = Force of static friction.
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