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Solve (a-b)(b+a)?

Solve (a-b)(b+a)?

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Answers (3)

2 months ago
2 months ago
I am not going to assume A, B are real numbers. A and B could be any mathematical objects that are
not Abelian under multiplication.
Yes, if A, B belong to an Abelian group/field under multiplication, thenAB+BA=0 , and
Dgentle Hero
2 months ago
just open the bracket to have:
ab+a^2-b^2-ba = a^2-b^2
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