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Solve (a-b)(b+a)?

Solve (a-b)(b+a)?

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Answers (3)

EmX
2 months ago
isaaq
2 months ago
solution.
I am not going to assume A, B are real numbers. A and B could be any mathematical objects that are
not Abelian under multiplication.
So(A-B)(A+B)=A^2-AB+BA-
Yes, if A, B belong to an Abelian group/field under multiplication, thenAB+BA=0 , and
(A-B)(A+B)=A^2+B^2
Dgentle Hero
2 months ago
(a-b)(b+a)
just open the bracket to have:
ab+a^2-b^2-ba = a^2-b^2
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