When 2.86g of a mixture of 1-butene (C4H8) and butane (C4H10) was burned in excess...
When 2.86g of a mixture of 1-butene (C4H8) and butane (C4H10) was burned in excess...
When 2.86g of a mixture of 1-butene (C4H8) and butane (C4H10) was burned in excess oxygen, 8.80g of CO2 and 4.14g of H2O were obtained. Calculate the percentage by mass of C4H8 and C4H10 respectively in the original mixture? [H=1 C=12]. And please show workings?
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Asked by brainz on 16th February, 2019
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