A lead is projected from the ground level with a velocity u at an angle Φ to the horizontal. Given that the time t, for the lead shot to reach the maximum height is t=usinΦ/g, where g is the acceleration of free fall due to gravity.
Show that the greatest height reached by the body is:
H=u^2Sin^2/2g.
It's a WAEC June 2001question?
In Physics
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Asked by Muna on 3rd November, 2018
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