0.61mol of copper (II) sulphite is treated with nitric acid according to the equation: 3CuS+8HNO3→...

0.61mol of copper (II) sulphite is treated with nitric acid according to the equation:
3CuS+8HNO3→ 3Cu(NO3)2+3S+2NO+4H2O. How many moles of copper(II) nitrate could be produced?

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Asked by Adaora on 18th April, 2018

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