In a triangle ABC, AD, BE, CF are its median intersecting at a, prove that...

In a triangle ABC, AD, BE, CF are its median intersecting at a, prove that 2AD + 3BC >4BE?

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Answers (1)

asamibobo12345
1 month ago
proof
since AD,BE and CF intersect at a
hence a coordinate a(x,y) such that AD=BE=CF
hence
AD+AD=BE+BE+BC-BC
implie that
2AD>2BE+BC-4BC
2AD+3BC>2BE
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