A coin place below a rectangular glass block of thickness 9cm and refractive index 1.5 is viewed vertically above the block. The apparent displacement of the coin is

clemtommy

12 years ago

does it mean dat,Real deepth-Apparent deepth=apparent displacement?i.e 9-6=3?

Parafc

1 year ago

Apparent displacement ( d) =t (1-1/n)
when t is tickness, and n is refractive index
: d= 9×(1-1/1.5)
d=9×0.33
d=3cm

MhizDee430

1 year ago

Easy formula:
Refractive index = -thickness/Apparent displacement -thickness
n=-t/D-t

Using it to solve the question:
n=-t/D-t
cross multiply
n×D-t=-t
D=-t/n +t
Putting our values
D= -9/1.5 +9
D=-6 +9
D=3m

Daniellenn

2 years ago

A coin place below a rectangular glass block of thickness 9cm and refractive index 1.5 is viewed vertically above the block.The apparent displacement of the coin is

paulo_pulisic

2 years ago

d=t×(1−
n
1

)

Where:

�
t is the thickness of the glass block.
�
n is the refractive index of the glass.

samlaz

2 years ago

Answer