A particle in circular motion performs 30 oscillation in 6 seconds. Its angular velocity is
a
5 rad s-1
b
6 rad s-1
c
5π rad s-1
d
10π rad s-1
Explanation
Correct Option
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Shemasane
5 years ago
Period = time/oscillation = 6/30=1/5s
Frequency=1/period
F=1/1/5=5Hz
Finding the angular velocity in term of π
Angular velocity= 2πF = 2*5*π=10πrad/s
