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The ratio of electrostatic force F\(_E\) to gravitational force F\(_G\) between two protons each of...

Physics
JAMB 2001

The ratio of electrostatic force F\(_E\) to gravitational force F\(_G\) between two protons each of charge e and mass m, at a distance d is

  • A. \(\frac{e}{4πε_oGm}\)
  • B. \(\frac{e^2}{Gm^2}\)
  • C. \(\frac{Gm^2}{4πε_oe^2}\)
  • D. \(\frac{e^2}{4πε_oGm^2}\)
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Correct Answer: Option D
Explanation

Electrostatic force = F\(_E\) = \(\frac{e^2}{4πε_od^2}\)

Gravitational force = F\(_G\) = \(\frac{Gm^2}{d^2}\)

\(\frac{F_E}{F_G}\) = \(\frac{\frac{e^2}{4πε_od^2}}{\frac{Gm^2}{d^2}}\)  =  \(\frac{e^2}{4πε_oGm^2}\)

NOTE: (d\(^2\)s canceled out)

 

There is an explanation video available below.


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Explanation Video

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