The effective capacitance between points X and Y in the diagram above is 1.0\(\mu\) F. What is the value of the capacitance?
Effective capacitance across the parallel = C + C = 2C
Effective capacitance across the circuit = \(\frac{1}{2C} + \frac{1}{2}\) = \(\frac{1 + C}{2C}\)
∴ Effective capacitance across the circuit = \(\frac{1 + C }{2C}\) = \(\frac{1}{1}\)
1 + C = 2C;
2C – C = 1
∴ C = 1.0 μ
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